Call the rate in still water vs;
upstream you have: vs-v=6/4
downstram you have: vs+v=6/3
where v is the rate with which the river flows.
rearranging:
vs-v=3/2
vs+v=2
from the second you have v=2-vs substitute into the first:
vs-2+vs=3/2
2vs=7/2
vs=7 mi/hr
A = h(b/2)
So the height is 8 and the base is 5
A = 8(5/2)
A = 20
I hope this helps! :)
~Ayden
Answer:
![\left[\begin{array}{cc}6&32\\39&15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2632%5C%5C39%2615%5C%5C%5Cend%7Barray%7D%5Cright%5D)
its the third option
Step-by-step explanation:
times each element by a half
As long as 2 opposite sides are the same and the other two opposite sides are the same. eg. 6,6,2 &2 / 1,1,7 & 7 and so on
Answer:
f^-1(x) = x+1
Step-by-step explanation:
y = x-1
x = y-1
y = x+1
