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olasank [31]
2 years ago
14

HEEEELLLLLLPPP !!!!!!!! What is the product ?

Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

\left[\begin{array}{cc}6&32\\39&15\\\end{array}\right]      its the third option

Step-by-step explanation:

times each element by a half

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Lilah is moving from Portland to Seattle. It takes her 3 hours to go by train. Mason leaves the train station in Portland and dr
s2008m [1.1K]

Answer:Lilah's speed on the train is 60 mph and Mason's speed is 75 mph

Step-by-step explanation:

Let x represent the speed of Lilah.

Lilah is moving from Portland to Seattle. It takes her 3 hours to go by train.

Distance = speed × time

Distance covered by Lilah in moving from Portland to Seattle would be

3 × x = 3x

It takes him 2.4 hours to get to Seattle, driving at 15 miles per hour faster than the speed of the train.

It means that Mason's speed is

x + 15

Distance covered by Mason would be

2.4(x + 15) = 2.4x + 36

Since the distance from Portland to Seattle is the same, then

3x = 2.4x + 36

3x - 2.4x = 36

0.6x = 36 x = 36/0.6 = 60 mph

Mason's speed would be 60 + 15 = 75 mph

7 0
3 years ago
Solution to this system of linear equation <br> -6x=48-6y<br> -4x=50-6y
MrRa [10]

Answer:

\large\boxed{x=1,\ y=6\to(1,\ 6)}

Step-by-step explanation:

\left\{\begin{array}{ccc}-6x=48-6y&\text{change the signs}\\-4x=50-6y\end{array}\right\\\underline{+\left\{\begin{array}{ccc}6x=-48+6y\\-4x=50-6y\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it ot the first equation:}\\-6(1)=48-6y\\-6=48-6y\qquad\text{subtract 48 from both sides}\\-54=-6y\qquad\text{divide both sides by (-6)}\\9=y\to y=6

7 0
3 years ago
You don't have to answer number 15. but pls answer the rest!
RoseWind [281]

Answer:

Step-by-step explanation:

13. 2,300mg > 2g

14. 3kg = 3,000g

16. 4120mg = 4.12g

17. 75g < 800mg

3 0
3 years ago
15 / √31 - 4
NeX [460]

Answer:

\frac{15}{ \sqrt{31} - 4}} = \sqrt{31} + 4

Step-by-step explanation:

\frac{15}{\sqrt{31} - 4}\\\\=\frac{15}{\sqrt{31} - 4} \times \frac{\sqrt{31} + 4}{\sqrt{31}+ 4} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   [  \ rationalizing \ the \ denominator \ ]\\\\=\frac{15( \sqrt{31} + 4 )}{(\sqrt{31})^2 - (4)^2}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ [ \ (a-b)(a+b) = a^2 - b^2 \ ]\\\\=\frac{15 ( \sqrt{31} + 4)}{31 - 16}\\\\=\frac{15 (\sqrt{31} + 4)}{15}\\\\= \sqrt{31} + 4

6 0
2 years ago
A store sells school bags for $17.10 each. At what price should the store sell each bag, if the price needs to be marked up by 3
valentinak56 [21]

Answer:

22.20

Step-by-step explanation:

17.10/10

1.710x3

5.1+17.10

22.20

6 0
3 years ago
Read 2 more answers
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