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tatiyna
3 years ago
6

How much will the monthly payment be for a 2 year old used car that's is priced at 13995 of the current finance rate is 48 month

s at 4.36% ? You will finance the 8% tt&l and make a 30% down payment
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:that’s a tough one

Step-by-step explanations just need some credit on brainly

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My book is 58 pages. I have already read 13 pages. I plan to read 5 pages each day until I finish the book.
ELEN [110]
C. (58-13)÷5=d

hope this helps, Buddy
6 0
3 years ago
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What is the answer ????????????????????
solniwko [45]
5.8 months hope it helps
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3 years ago
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I will mark the correct answer as brainliest! A piece of fabric 180 inches long is cut in 2 pieces such that 3 times the larger
Ulleksa [173]
Let one piece be x inches long then the other piece is  180-x inches long.

3x > 4 (180-x)
3x > 720 - 4x
7x > 720

x > 103 6/7 ins

the 2 pieces could be 107 inches and 180-107 = 73 inches

5 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with M = 0.03, \pi = 0.21

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}

n = 382.23

Rounding up

We need a sample size of at least 383.

6 0
3 years ago
Solve for angle 1 i got an answer but i dont know if it’s right
Alexeev081 [22]

Answer:

73

Step-by-step explanation:

72 - 35 = 107

180 - 107 = 73

107 + 73 = 180

4 0
3 years ago
Read 2 more answers
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