Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
In y = mx+b, m is the term that refers to slope
hope this helps
Answer:
41/35
Step-by-step explanation:
Simplify the following:
4/7 + 3/5
Put 4/7 + 3/5 over the common denominator 35. 4/7 + 3/5 = (5×4)/35 + (7×3)/35:
(5×4)/35 + (7×3)/35
5×4 = 20:
20/35 + (7×3)/35
7×3 = 21:
20/35 + 21/35
20/35 + 21/35 = (20 + 21)/35:
(20 + 21)/35
| 2 | 1
+ | 2 | 0
| 4 | 1:
Answer: 41/35
Answer:
A, D
Step-by-step explanation:
When we multiply the fractions, we can get:
This is also equivalent to:
When looking at the answer choices, the only ones that equal are A and D because:
