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Nookie1986 [14]
3 years ago
15

What is 15÷1/9= __________

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

THE ANSWER IS 135!!!

Step-by-step explanation:

Pretend 15 is 15/1. Then use cross multiplication to divide the two fractions.

15/1 divided by 1/9 = 15/1 * 9/1 = 15 *9 = 135

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The graph of F(x) shown below resembles the graph of G(x) = x ^ 2 but it has been changed somewhat . Which of the following coul
sukhopar [10]

Answer:

f(x) = 3x^{2} + 2

Step-by-step explanation:

Given G(x) = x^{2}

As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)

=> f(x) = ax^{2} + 2

As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3

and there is no reflection, so a= 3

=> the  equation of f(x) is:  f(x) = 3x^{2} + 2

5 0
3 years ago
Which expression is equivalent to the given expression?
USPshnik [31]

Answer:

A.

Step-by-step explanation:

The a^3 would cancel out, currently leaving just b^5 on the top and ab on the bottom. The b would also cancel out, finally leaving just b^4/a. Therefore A is the answer equivalent to the original expression.

3 0
2 years ago
Solve this problem. 4|3x+4|=4x+8
Gelneren [198K]
The correct answer is x= -1. Hope this helps!!
6 0
3 years ago
What is the volume of a cylinder with a diameter of 10 meters and a height of 8 meters? Use 3.14
Pachacha [2.7K]
Answer 20 I just did that question
5 0
3 years ago
The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an
Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w  feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = \dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, w = \dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}

Or, w = \dfrac{-11\pm \sqrt{473}}{2}

or, w = \dfrac{-11\pm 21.7}{2}

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0
3 years ago
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