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fiasKO [112]
3 years ago
10

Why wont anybody answer any of my questions ever!

SAT
1 answer:
sveta [45]3 years ago
8 0

Answer:

Try to give more points.

Explanation:

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A group of campers walked at a speed of 4. 5 mph from their campsite to a rest area. Their return trip to the campsite took 15 m
tia_tia [17]

The distance between the campsite and the rest area is 9 miles.

The given parameters:

  • <em>Initial speed of the campers, u = 4.5 mph</em>
  • <em>Final speed of the campers, v = 4 mph</em>

<em />

Let the time of motion from the campsite to rest area = t (hours)

Time for return trip = t hours +  15 mins

                               = (t + 0.25) hours

Let the distance between the campsite and rest area = d

d = 4.5t

d = 4(t + 0.25)

4.5t = 4(t + 0.25)

4.5t = 4t + 1

4.5t - 4t = 1

0.5t = 1

t = 2 hours

The distance between the campsite and the rest area is calculated as follows;

d = 4.5t

d = 4.5 x 2

d = 9 miles

Thus, the distance between the campsite and the rest area is 9 miles.

Learn more about distance and speed here: brainly.com/question/2854969

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