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Westkost [7]
2 years ago
9

If you divide a number into 3 equal groups and then divide each group in half, you end up with 13. The starting number is.

SAT
1 answer:
Vlad [161]2 years ago
7 0

Answer:

The starting number is 78.

Explanation:

(x / 3) / 2 = 13

divide a number by 3 (x / 3)

divide in half (x / 3) / 2

You get 13 (x / 3) / 2 = 13

Reverse the problem.

13 * 2 = 26

26 * 3 = 78

x = 78

Plug in the number.

(78 / 3) / 2 = 13

78 / 3 = 26

26 / 2 = 13

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What is the probability that a randomly chosen u. S. President is left-handed and a democrat?.
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Using conditional probability, it is found that there is a 0.052 = 5.2% probability that a randomly chosen U. S. President is left-handed and a democrat.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: President is left-handed.
  • Event B: President is a democrat.

Researching the problem on the internet, it is found that:

  • 40% of the presidents were left-handed, hence P(A) = 0.4.
  • If a president is left-handed, there is a 13% chance that the president is a Democrat, hence P(B|A) = 0.13.

Then:

P(B|A) = \frac{P(A \cap B)}{P(A)}

0.13 = \frac{P(A \cap B)}{0.4}

P(A \cap B) = 0.13(0.4)

P(A \cap B) = 0.052

0.052 = 5.2% probability that a randomly chosen U. S. President is left-handed and a democrat.

You can learn more about conditional probability at brainly.com/question/15536019

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