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shtirl [24]
3 years ago
7

The air in the atmosphere circulates mainly because _____.

Computers and Technology
2 answers:
MakcuM [25]3 years ago
6 0

The answer is C, covection is redistributing heat

sesenic [268]3 years ago
3 0
The answer is <span>convection is redistributing heat.  Convection as warm air goes up and once it is cooled it goes back down again.  Cool air is more heavy than warm air because it is more dense.  Its particles are more closer together than warm air.</span>
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The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
4 years ago
One disadvantage of using the styles feature of a word processor is that you cannot modify existing styles. true or false
gayaneshka [121]
I think its false
but im not possitive

8 0
3 years ago
After Brooke has helped Simon to resolve his original problem, Simon asks her about another linked workbook he has received. The
amm1812

Answer:

The answer is "The working book can be opened and the version Links dialogue box will press Continue button".

Explanation:

As we knew, the workbook is a set of files, in which one or more worksheets are uses. All the file of the workbook is defined in the form of the sheets, like Sheet1, Sheet2, and so on, in which we can also change the name of the sheet.

  • To solve another workbook problem the firstly the Simon open the workbook by providing the appropriate link.
  • This file Includes the source file, that doesn't have published, and  he also wants to use the workbook with the new source file values.
7 0
3 years ago
What do you think about the future of Moore’s Law? Will it continue to hold true? Will other technologies help us keep on track?
Sveta_85 [38]

There will come a time when Moore's law can no longer hold true. Past a certain point, it will be physically impossible to make a transistor any smaller. Microscopic technology will always be limited by the size of an atom. Yes, Moore's law can be regarded as a self-fulfilling prophecy, because tech companies do not want to fail to keep up with it.

4 0
3 years ago
How do you record your own video game Music and post Them on yt
Alex777 [14]

Answer:I would try downloading a beat app and making a song,then posting

Explanation:

8 0
3 years ago
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