9514 1404 393
Answer:
23
Step-by-step explanation:
Let J represent Jiri's age. Then Pamela's age is 2J and the sum of their ages is ...
J + 2J = 69
3J = 69 . . . . .collect terms
J = 23 . . . . . . divide by 3
Jiri's age is 23.
Answer:
32.43
Step-by-step explanation:
To get the standard divisor
We sum up the tickets sold
Applejack's = 66 tickets
Broncos = 769 tickets
Colts = 652 tickets
Deers = 556 tickets
The total prize amount = $63
Total tickets = 66 + 769 + 652 + 556 = 2043
Standard divisor = 2043/63
= 32.43
The standard divisor to two decimal places is 32.43
Answer:
TRUE!!!!!!!!!!!!!!!!!! BRANLIST
Step-by-step explanation:
4 out of 10 because the amount of prime numbers from 1- 10 is
2, 3, 5, and 7.
Hope this helps!
Answer: ![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.
Step-by-step explanation: Given radical expression
![\sqrt[3]{5x} \times \sqrt[3]{25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D)
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and
Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
.</h3>
