1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ziro4ka [17]
3 years ago
6

What is the measure of angle CED?

Mathematics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

m  

Step-by-step explanation:

we know that

Triangles ABC and CDE are similar triangles, because the corresponding angles are congruent

m ------> by vertical angles

m ----> given problem

m ----> The sum of the internal angles of the triangle must be equal to 180 degrees

we have

m

so

m


ANEK [815]3 years ago
3 0
Angle CED must also measure 60°. 
Because angle m is shown to be congruent to angles ABC and CDE, this means that angle m has a measure of 60 degrees.
There can only be 180 degrees in a triangle, so the measure of angle ACB must be 180-60-60, which equals 60 degrees.
Using the Vertical Angles Theorem, the measure of angle ACB is the same as the measure of angle CED.
Therefore, angle CED measures 60°.
You might be interested in
Find the coordinates of the image after a reflection across the line y = x.
Marat540 [252]

Answer:

(2 1) for L (4 3) for G  (4 -1)

Step-by-step explanation:

5 0
3 years ago
A stockbroker sold 70 shares of stock $14.52 each. what was the total amount of the sale?
Olenka [21]

Answer:

$1016.4 - if this is just a simple multiplication question

7 0
3 years ago
Will someone please answer this and remind me how to solve this
Veseljchak [2.6K]

Answer:

Step-by-step explanation:

Since the two triangles are similar, you can use proportions to solve for the value of x

\frac{x}{12}  = \frac{4}{3}

Now, just multiply 4 and 12.

4 * 12 = 48

Then divide that by 3.

48 / 3 = 16

Therefore, x = 16.

5 0
3 years ago
Read 2 more answers
If the student is a domain/inout and the hair color is the range/output how is these two set of relation not a function?
IRINA_888 [86]

Answer:

A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.

Such that each input can be mapped into only one output.

So for example, if we have a relation that maps the input 2 into two different values:

f(2) = 4

f(2) = 8

Then this is not a function.

In the case of the problem, we have a student as the input, and the hair color as the output.

So we will have something like:

f(student) = blond

And if this student decides to change his/her hair color to red?

Then the function becomes:

f(student) = red

So for the same input, we had two different outputs, which means that this is not a function.

We also could have the case where a given student has two colors (Californian for example)

Where again, we would see two different outputs for one single input.

6 0
2 years ago
Central City High’s basketball team will be entering the playoffs at the end of their regular season. There will be 3 other team
anygoal [31]
The answer is   C.99 < x < 315
8 0
3 years ago
Read 2 more answers
Other questions:
  • 60 is 25% of what number?
    5·2 answers
  • 4:x::5:15 SLOVE IT AND EXPLAIN
    15·1 answer
  • Use the diagram to find the measure of angle 1 and measure of angle 2
    14·1 answer
  • AC is diagonal of square ABCD, and the length of AC is 4. What is the area of the square?
    6·1 answer
  • Help ASAP with #2 no links or I will report
    14·1 answer
  • The domain of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is (1 point)
    9·1 answer
  • Jina's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Jina $4.35 per pound, and type B
    14·1 answer
  • Using the graph , determine the coordinates of the vertex of the parabola
    15·1 answer
  • PLEASE HELP THANKS.
    5·2 answers
  • Please HELP ME FIGURE THIS OUT ( ITS REALLY EASY IM JUST TIRED )
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!