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Makovka662 [10]
2 years ago
6

Pls help pls TT,,,,,,

Mathematics
1 answer:
mamaluj [8]2 years ago
4 0
The anscer is c x=14
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Ir[ Fairbanks, the temperature at 6:00 AM on Sunday is - 48°F. The weather forecast
mestny [16]

Answer:

The answer is 3 days

Step-by-step explanation:

Divide 48/16=3

6 0
3 years ago
The top of a table is a parallelogram with a base of 28 cm and a height of 20 cm. Patty wants to cover the table with tiles that
suter [353]

The area of the top of the table is 28 × 20 = 560 cm2. The area of Patty’s tiles is 8 cm2 each and the area of Jake’s tiles is 9 cm2 each. Patty will need 560 ÷ 8, or 70, tiles. Jake will need 560 ÷ 9, or about 63, tiles. So, Patty will use about 7 more tiles.

3 0
3 years ago
Read 2 more answers
If you were to roll the dice one time what is the probability of it landing on an odd number?
yanalaym [24]

Answer:

1/2

Step-by-step explanation:

a dice has six sides and the highest number is 6

the dice should have the numbers

1,2,3,4,5,6

which 1,3,5 are odd numbers so it's a 1/2

3 0
2 years ago
Help me please :((: thank u
I am Lyosha [343]

Hey there!

In order for you to find the one that is equivalent to the given expression is to COMBINE YOUR LIKE TERMS then work from there!

12q + q^2 - 8 + q = ?

(q^2) + (12q + q) + (-8)

q^2 = q^2 since it doesn't have any like term(s)

12q + q = 12q + 1q = 13q

-8 = -8 since it doesn't have any like term(s)

Put all the numbers we solved for in An equation and Thats your answer!

If you did it correctly you should have: q^2 + 13q - 8

Answer: q^2 + 13q - 8 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
2 years ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
2 years ago
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