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3 years ago

Which property is illustrated by the statement 8 + 2 = 2 + 8?

Mathematics

2 answers:

cricket20 [7]3 years ago

6 0

Answer:

commutative

Step-by-step explanation:

MatroZZZ [7]3 years ago

5 0

Answer:

Associative

Step-by-step explanation:

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INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?

Kay [80]

There are an infinite number of them.
Here are a few:

2.1
2.2
2.3
2.3000000001
2.30000000000000006
2.5
2.00009
.
.
etc.

How to find them:

You probably never heard this before, but I'll bet
you'll remember it from now on:

<em>ANY number that you can write down on paper completely, </em><em>using digits
and a decimal point if you need it but no symbols, is a rational number.</em>

If you can write it down completely without any 'comments', then it's rational.

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3 years ago

A helicopter hovers 650 feet above a small island. The figure shows that the angle of depression from the helicopter to point P

Anettt [7]

See the attached picture:

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3 years ago

My brother needs help with his math homework and I don't understand this?need help.

Olin [163]

To answer the problems correctly, you have to follow and pay close attention to whether or not it says "Area" or "Perimeter". For example, for the first problem, area of 63 square units, you would have to create a shape thats sides multiply out to equal 63 units squared. He could draw a square with 9 units by 7 units. This would work because 9x7=63. For perimeter, all four sides must add up to equal 38 units. Feel free to get creative with the shape on this one! If you have any other questions, just ask. Hope I helped some. :)

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3 years ago

Ty is right inches taller than his brother Reece if ty is 42 inches tall how tall is Reece. Write an equation using a variable r

fgiga [73]

Mi llamos Bryson y tu ¿

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4 years ago

Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.

Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

$P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}$

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

$P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}$

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

$P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420$

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0

3 years ago