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3 years ago

Please Help With This Question?!?

Mathematics

1 answer:

posledela3 years ago

6 0

Answer:

Step-by-step explanation:

negative

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What are the common multiples of 8,10,12?

timurjin [86]

The answer is 1 & 2

Hope this helps!

4 0

3 years ago

Read 2 more answers

For the inequality, find TWO values for x that make the inequality true: 5x<2

dangina [55]

Answer:

a and c

Step-by-step explanation:

5(-2)<2

-10<2

5(-5)<2

-25<2

7 0

3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

2 years ago

Pleasee help me guyss .

Setler79 [48]

Answer:

24%

Step-by-step explanation:

25 - 19 = 6

25 = 100%

2.5 = 10%

1.25 = 5%

0.25 = 1%

5 = 20%

1 = 4%

6 = 24%

Hope this helps :)

3 0

3 years ago

Read 2 more answers

What is the volume of a cone-shaped popcorn cup that is 8 inches tall and 6 inches across at the base?

Alina [70]

The volume of cone shaped popcorn cup is 75.36 cubic inches.

According to the given question.

The height of the popcorn cup = 8inches

And the diameter of the cup = 6 inches

⇒ Radius of the popcorn cup = 6/2 = 3 inches

As we know that, the volume of cone is calculated by the formula

volume of cone = (πr^2h)/3

Therefore, the volume of cone shaped popcorn cup

= 3.14((3)^2)(8)/3

= 3.14(3)(8)

= 75.36 cubic inches

Hence, the volume of cone shaped popcorn cup is 75.36 cubic inches.

Find out more information about volume of cone here:

brainly.com/question/23173618

#SPJ4

8 0

1 year ago