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3 years ago

A falcon flying 55 mph crosses a lake in 1 minute. How long would it take a hummingbird flying 45 mph to cross the same lake?

Mathematics

2 answers:

OverLord2011 [107]3 years ago

7 0

Answer:

1 2/9 minutes

Step-by-step explanation:

55 mph

55 / 60 = 11/12

11/12 of a mile = 1 minute

45 mph

45 / 60 = 3/4

3/4 of a mile = 1 minute

11/12 divided by 3/4

11/12 * 4/3

We can cross-cancel

11/3 * 1/3 = 11/9 = 1 2/9

It takes 1 2/9 minutes for the hummingbird to cross the lake

Hope this helps!

(Please let me know if I did something wrong!)

Rufina [12.5K]3 years ago

5 0

Answer:

1 2/9 minutes

Step-by-step explanation:

55 mph

55 / 60 = 11/12

11/12 of a mile = 1 minute

45 mph

45 / 60 = 3/4

3/4 of a mile = 1 minute

11/12 divided by 3/4

11/12 * 4/3

cross-cancel

11/3 * 1/3 = 11/9 = 1 2/9

It takes 1 2/9 minutes for the hummingbird to cross the lake

Hope this helps!

if it does, Brainlest pls!!!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

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so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

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By definition of variance, we have

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For a string consisting of one letter, we have

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so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

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stiks02 [169]

Answer: 82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB $=\sqrt{(9+1)^2+(-1-7)^2}$ units [By distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

$=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}$ units

Width = BC = $\sqrt{(-1+5)^2+(7-2)^2}$ units

$=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}$

Area = length x width

= $2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}$

Hence, the area of the rectangle is 82 sq. units .

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Fed [463]

Answer:

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Step-by-step explanation:

A function f(x) translated right h units and up k units will become ...

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