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FinnZ [79.3K]
3 years ago
12

I need this really quick please.

Mathematics
2 answers:
salantis [7]3 years ago
8 0

Answer:

7x-6

Step-by-step explanation:

Anestetic [448]3 years ago
7 0
The correct answer is 7x-8
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7 − 3x + 3 + 8x combining like terms
Lemur [1.5K]

Answer:

10+5x

Step-by-step explanation:

7 and 3 are like terms and 7+3=10

-3x and 8x are also like terms and -3x+8x=5x

Therefore you have 10+5x

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Solve expression completely.<br> 64°<br> O<br> 1<br> O 64<br> O Unknown
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3 0
3 years ago
The total cost (in dollars) for a company to manufacture and sell x items per week is C=40x+180, whereas the revenue brought in
crimeas [40]

Answer:

The company needs to sell either 30 or 40 items.

Step-by-step explanation:

We are given that the cost for selling <em>x</em> items given by the function:

C(x)=40x+180

And the revenue for selling <em>x</em> items is given by:

R(x)=68x-0.4x^2

The profit function is the cost function subtracted from the revenue function:

P(x)=R(x)-C(x)

Substitute and simplify:

\displaystyle \begin{aligned} P(x)&=(68x-0.4x^2)-(40x+180)\\&=68x-0.4x^2-40x-180\\&=-0.4x^2+28x-180\end{aligned}

To find how many items must be sold in order to obtain a weekly profit of $300, we can let <em>P</em> equal 300 and solve for <em>x</em>. So:

300=-0.4x^2+28x-180

Solve for <em>x</em>. Subtract 300 from both sides:

-0.4x^2+28x-480=0

We can divide both sides by -0.4:

x^2-70x+1200=0

Factor:

(x-40)(x-30)=0

Zero Product Property:

x-40=0\text{ or } x-30=0

Solve for each case:

x=40\text{ or } x=30

So, in order to obtain a weekly profit of $300, the company need to sell either 30 <em>or</em> 40 items.

7 0
3 years ago
Need Help Rn!!!
fgiga [73]
It would be 5850 hope you get it right:)
7 0
3 years ago
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