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madam [21]
3 years ago
13

Josh is solving the equation 2 % + 2% and predicts that his

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

i believe the answer is yes he is correct

Step-by-step explanation:

2x3=6

2x8=16

7/3+20/8=56/24+60/24=116/24=4 5/6

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

No ......................xD

Miss Looking So cute

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China has a population of approximately 1,322,000,000 people. Express this number in scientific notation. A) 1.322 x 109 B) 1.32
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What is 3.625 written as a fraction in lowest terms?
NemiM [27]

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29/8 with 3 inside or 3 5/8

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Find the lateral area for the prism. L.A. =<br> Find the total area for the prism. T.A. =
Ksivusya [100]
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
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L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2

The total are will be given by:
T.A=L.A+base area
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thus;
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6 0
4 years ago
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Please help!<br>what polynomial must be added to <br>−5x^3 + 4x − 3 so that the sum is x^2 − x − 1?
lakkis [162]
<h3><u>Solution:- </u></h3>

Let the number to be added be A

Now,

\begin{gathered}\implies\quad \sf −5x^3 + 4x − 3  + A = x^2 − x − 1 \\\end{gathered}

Transposing (−5x³+ 4x − 3 ) to other side-

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 -( −5x^3 + 4x − 3) \\\end{gathered}

Remember if there is a -ve sign before a bracket the signs of whole of the terms changes on opening bracket

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 + 5x^3 - 4x + 3\\\end{gathered}

Putting like terms together -

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 - x -4x +3 -1  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 -5x +2 \\\end{gathered}

\longrightarrowTherefore, 5x³+x²-5x +2 should be added to −5x³+ 4x − 3 to get x²− x − 1

6 0
3 years ago
Help with question 2a and b?
Aleonysh [2.5K]
If it is a single transformation, it will need to be a homothetic transformation.
None of the points remain at the old place, so it cannot be a scaling problem with respect to one of the existing points.

A homothetic transformation is bacically a scaling problem, with respect to an arbitrary point called the homothetic centre.
The centre, O,  if it exists, is along the point joining any original point and the transformed point.

Here, take a pencil (imaginary one if you wish) and join points AA', BB', CC', DD', EE' and you will find that they are concurrent at point O (3,-6).
So O(3,-6) is the centre of homothety.

The scale factor, as usual, is AO/A'O, or BO/B'O... for transformation from X to Y  (X is ABCDE), or the reciprocal if it is from Y to X.


7 0
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