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madam [21]
3 years ago
13

Josh is solving the equation 2 % + 2% and predicts that his

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

i believe the answer is yes he is correct

Step-by-step explanation:

2x3=6

2x8=16

7/3+20/8=56/24+60/24=116/24=4 5/6

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

No ......................xD

Miss Looking So cute

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Cuánto le falta a 1/4 para llegar a 4/5​
german

Answer:

4/5 - 1/4

Step-by-step explanation:

4/5 =0.8

1/4=0.25

  ⇒0.8 - 0.25 = 0.55 (decimal form)

  ⇒4/5 - 1/4 = 11/20 (exact form-fraction)

6 0
3 years ago
PLEASE HELP ASAP 25 POINTS
motikmotik

Answer:

it's b

Step-by-step explanation:

If you can use your phone in class, I highly suggest the desmos app because you can just put the equations in and it shows you everything


6 0
3 years ago
Someone pls help me i will give brainly when 2 people answer<br><br> No bots or ill report!!!!
Korvikt [17]

Answer:

(-3,-3)

(-4,-1)

(-2,-1)

Step-by-step explanation:

Hope this helps!

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7 0
3 years ago
Read 2 more answers
Escribe la posición del móvil si el diámetro de la trayectoria es de 10 m y la distancia recorrida es de 190 m
lions [1.4K]

Step-by-step explanation:

La posici´on de una part´ıcula que se mueve unidimensionalmente esta definida por la ecuaci´on:

x(t) = 2t

3 − 15t

2 + 24t + 4 donde 0x

0 y

0

t

0

se expresan en metros y segundos respectivamente. Determine:

a. ¿Cu´ando la velocidad es cero?

b. La posici´on y la distancia total recorrida cuando la aceleraci´on es cero.

Soluci´on:

a. Recordemos que:

v(t) =

dx

dt =

d

dt(2t

3 − 15t

2 + 24t + 4) = 6t

2 − 30t + 24

Sea t

0

el tiempo en que la velocidad se anula, entonces v(t

0

) = 0.

De este modo:

0 = v(t

0

) = 6(t

0

)

2 − 30(t

0

) + 24 = 6[(t

0

)

2 − 5(t

0

) + 4] = 6[(t

0

) − 4][(t

0

) − 1]

As´ı tenemos que:

t

0

1 = 4, t

0

2 = 1

De este modo, tenemos que la velocidad se anula al primer segundo y a los cuatro segundos.

b. Recordemos que:

a(t) =

dv

dt =

d

dt(6t

2 − 30t + 24) = 12t − 30

Ahora sea t

0

el instante en que la aceleraci´on se anula, entonces a(t

0

) = 0

Ahora:

0 = a(t

0

) = 12t

0 − 30

As´ı tenemos que: t

0 =

30

12 =

5

2

Por lo tanto, la posici´on en este instante es:

x(t

0

) = x

5

2

= 2

5

2

3 − 15

5

2

2 + 24

5

2

+ 4 = 125

4 − 3

125

4 + 60 + 4 = −2

125

4 + 64 = −

125

2 +

128

2 =

3

2

De este modo, la posici´on de la part´ıcula cuando la aceleraci´on es cero es de 3

2 metros.

Adem´as la distancia total recorrida esta dada por:

distancia = |x(t

0

) − x(0)| = |

3

2 − 4| =

5

2

Finalmente la distancia total recorrida es: 5

5 0
2 years ago
Complete the sentence what numbers are it? Do it in order and tell me “ top= “ and then “bottom number = “
pav-90 [236]

Answer:

one half is shaded therefore one is on top and two is on the bottom

6 0
3 years ago
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