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2 answers:
Answer:
The answer is triangle PST is similar to triangle SRT
Step-by-step explanation:
In the given figure ∠PQR = ∠SRT= ∠PTS =90°
By AA similarity rule we prove the two triangles similar.
In triangle SRT and PST
∠SRT = ∠PTS (both right angles i.e both 90°)
∠RST = ∠PST (common)
Hence, by AA rule
Therefore, Triangle SRT and PST are similar
The answer is Triangle PQR
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Answer: Yes
Step-by-step explanation:
The correct answer should be c) 3.
Find BC
AC^2=AB^2+BC^2
20^2=16^2+BC^2
400=256+BC^2
BC=√(400-356)
BC=12
Use SOHCAHTOA
Sine A=12/20=3/5
COS A=16/20 =4/5
TAN A=12/16 =3/4
