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Sliva [168]
3 years ago
12

Help please

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
If Triangle ABC is similar to triangle DEF, then ∠A is congruent to ∠D, ∠B is congruent to ∠E, and ∠C is congruent to ∠F.

If ∠E = 40°, then ∠B = 40°.

There are 180° in a triangle. If ∠A = 35° and ∠B = 40°, then ∠C = 180° - 35° - 40°.

180 - 35 - 40 = 105°
m∠C = 105°
You might be interested in
an outdoor deck is 7 feet wide the perimeter of the deck is 64 feet what is the length of the deck use the numbers to write an e
ycow [4]
Answer: 25

Equation:
2(7)+2(x)=64
14+2x=64
2x=64
X=25

Hope this helps :)
5 0
3 years ago
Is (x-4) a factor of f(x) = x3 - 2x2 + 5x + 1? Use either the remainder theorem or the factor theorem to explain your reasoning.
Virty [35]

Answer:

(x-4) is not a factor of f(x)=x³-2x²+5x+1

Step-by-step explanation:

Uding the remainder theorem,(x-4) is a factor if the remainder is 0

Plug in x=4

(4)³-2(4)²+5(4)+1

64-32+20+1

64-53

11

7 0
2 years ago
Please answer with everything needed i appreciate everyones help
yawa3891 [41]
Recheck the answer with your teacher.

4 0
1 year ago
Read 2 more answers
Find the altitude of a cylinder with with a radius of 9 and a surface area of approximately 791.68 units2.
Vika [28.1K]

In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.

The formula of surface area of cylinder is

A= 2 \pi r^2 + 2 \pi r h

Substituting the values of A and r, we will get

791.68 = 2* \pi * 9^2  + 2 * \pi * 9*h
\\
791.68 = 162 \pi + 18 \pi h
\\
791.68 -162 \pi = 18 \pi h
\\
h = \frac{791.68 -162 \pi}{18 \pi}
\\
h =5 units

So the height of the cylinder is 5 units .


4 0
3 years ago
The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.
lora16 [44]

Answer:

The standard form as y=5x^2+30x+41

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of

Given y = 5(x+3)^2-4

Squaring  using (a+b)^2=a^2+b^2+2ab , we get,  

y=5(x^2+9+6x)-4

Multiply 5 inside , we get,

y=5x^2+45+30x-4

Solving further , we get,

y=5x^2+30x+41

Thus , we have obtained the standard form as y=5x^2+30x+41







8 0
2 years ago
Read 2 more answers
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