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3 years ago

PROSZĘ O SZYBKĄ POMOC! DAJE NAJ!

Mathematics

2 answers:

Marianna [84]3 years ago

4 0

Answer:

poghu singua lamdy

Step-by-step explanation:

#i,dont,know,your,language

svp [43]3 years ago

3 0

Nie mogę ci powiedzieć, że przepraszam stary, nie mówię po polsku

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(2x105)/(3x103) + 3x103 * 5x102

AleksAgata [21]

Answer:

1500066.66

Step-by-step explanation:

Given: $(2\times10^{5} )/(3\times 10^{3} ) + 3\times10^{3} \times 5\times10^{2}$

Now, simplifying it.

Using PEDMAS in solving the expression

First opening the parenthesis

= $2\times10^{5} /3\times 10^{3} + 3\times10^{3} \times 5\times10^{2}$

Next dividing the number

as per law of indices, $x^{m} \div x^{n} = x^{m-n}$

= $2\times10^{5-3} /3 + 3\times10^{3} \times 5\times10^{2}$

= $2\times10^{2} /3 + 3\times10^{3} \times 5\times10^{2}$

= $\frac{2\times10^{2} }{3} + 3\times10^{3} \times 5\times10^{2}$

Next multiplying the number as per PEDMAS

as per law of indices, $x^{m} \times x^{n} = x^{m+n}$

= $\frac{2\times10^{2} }{3} + 15\times10^{3+2}$

= $\frac{2\times10^{2} }{3} + 15\times10^{5}$

= $\frac{2\times 100}{3} + 15\times10^{5}$

Next dividing the number as per PEDMAS

= $2\times 33.33 + 15\times10^{5}$

Next multiplying the number as per PEDMAS

= $66.66+1500000$

Now adding the number

= 1500066.66

4 0

3 years ago

Problem Page At a certain college, 49% of the students are female, and 19% of the students major in civil engineering. Furthermo

SIZIF [17.4K]

Answer with Step-by-step explanation:

Let

A=Students are female

B=Students major in civil engineering

The probability that a students are female=P(A)= $\frac{49}{100}=0.49$

The probability that a student major in civil engineering=P(B)= $\frac{19}{100}=0.19$

The probability that students both are female= $P(A\cap B)=\frac{12}{100}=0.12$

a.We have to find the probability that a random selected female student major in civil engineering.

We have to find $P(B/A)$

$P(B/A)=\frac{P(A\cap B)}{P(A)}$

$P(B/A)=\frac{0.12}{0.49}=0.24$

Hence, the probability that a randomly selected female student majors in civil engineering=0.24

b.We have to find the probability that a random selected civil engineering major is female.

We have to find $P(A/B)$

$P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0.12}{0.19}=0.63$

Hence, the probability that a randomly selected civil engineering major is female=0.63

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