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vladimir2022 [97]
3 years ago
12

Find the geometric mean of 6 and 96.

Mathematics
1 answer:
Damm [24]3 years ago
7 0
The geometric mean of 96 and 6 is <span>24</span>
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The table represents a linear function. Find the values of A and B.​
bazaltina [42]

Answer:

The answers are that a = -5 and b = 1

Step-by-step explanation:

In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)

m(slope) = (y2 - y1)/(x2 - x1)

m = (11 - 5)/(-3 - 0)

m = 6/-3

m = -2

Now that we have this we can model this using point-slope form.

y - y1 = m(x - x1)

y - 5 = -2(x - 0)

y - 5 = -2x

y = -2x + 5

Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.

y = -2x + 5

15 = -2(a) + 5

10 = -2a

-5 = a

And we can also solve for b using the ordered pair (2, b)

y = -2x + 5

b = -2(2) + 5

b = -4 + 5

b = 1

4 0
3 years ago
5. photo album: $25.50, 10% markup
sasho [114]

Answer:

$28.05

Step-by-step explanation:

If you want to find how much the photo album is after the markup, you first have to find 10% of the original price. 10% of $25.50 is $2.55, so you add $2.55 and $25.50 to find the price after the markup.

Hope this helps!

3 0
3 years ago
.cuál es el resultado de 3.15+2​
sp2606 [1]

Answer:

3.15+2=5.15

The answer is 5.15.

6 0
3 years ago
Where is the point (-4 -5) located on the coordinate plane
Mademuasel [1]

9514 1404 393

Answer:

  D.  in quadrant III

Step-by-step explanation:

The signs of the coordinates tell you the point is located left of, and below, the origin (where the axes cross). That puts it in Quadrant III.

7 0
3 years ago
Read 2 more answers
Find the area of the trapezoid by composing into rectangles or decomposing into triangles or other shapes as needed. Show your w
mash [69]

So I decided to make a visual aid for this problem.

All of the work is outlined in the image.

Your final answer is 109.

Hope that helps!

7 0
4 years ago
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