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1 year ago

PLEASE HELP!!! FINDING PROBABILITY MATH!!! expert help would be nice

Mathematics

1 answer:

ozzi1 year ago

6 0

The probability that a person wins the game is 32.1%

<h3>How to illustrate the probability?</h3>

Based on the information given, the following can be depicted. It should be noted that there are 6 sides as well as 4 cards.

Therefore, the numbers on the dice i.e from 1 - 6 will be represented 4 times each. This gives a total of (4 × 6) = 24. There are also 4 cards. The total in sample space will now be:

= 24 + 4 = 28

The frequency table will be such that 28 or more have a relative frequency of 9. Therefore, the probability that a person wins the game will be:

= 9/28 = 32.1%

When you win 25% of the time, this illustrates that the number of products picked will be:

= 25% × 28

= 7 products.

The probability of participants achieving a winning score of 36 or higher in four consecutive attempts will be:

= 1/6⁴ = 1/1296

Learn more about probability on:

brainly.com/question/24756209

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Plz help!! And show work plz 18 points!

garri49 [273]

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4 0

3 years ago

Analyze the following table of values.<br><br> y=1/2x<br> y=1/2^x2+4<br> y=4^x2+1/2<br> y=4(1/2)x

Fittoniya [83]

The table models an exponential relationship, and the equation of the table is $y = 4(1/2)^x$

<h3>How to analyze the table of values?</h3>

The table of values is given as:

x 0 1 2 3 4

y 4 2 1 1/2 1/4

The above table shows an exponential model

An exponential model is represented as:

$y = ab^x$

When x = 0 and y = 4, we have

$ab^0 = 4$

Evaluate

a = 4

When x = 1 and y = 2, we have

$ab^1 = 2$

Evaluate

$ab = 2$

Substitute 4 for a

4b = 2

Divide both sides by 4

b = 1/2

Substitute 4 for a and 1/2 for b in $y = ab^x$

$y = 4(1/2)^x$

Hence, the equation of the table is $y = 4(1/2)^x$

Read more about exponential models at:

brainly.com/question/11464095

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6 0

2 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$