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2 years ago

3 erasers cost $4.41 What equation would help determine the cost of 4 erasers?

Mathematics

2 answers:

lina2011 [118]2 years ago

6 0

Answer:

Using this equation: f(x) = 1.47x

The cost of 4 erasers is 5.88

each costs 1.47

soldi70 [24.7K]2 years ago

3 0

Answer:

Well you can divide 4.41 by 3 and then use that number and multiply it by 4

Step-by-step explanation:

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Select all the common denominators for 8/3 and 5/6 .......12, 24, 32, 36, 48

BabaBlast [244]

Hello.

The answer to your question is =
12, 3 x 4 and 6 x 2.
24, 3 x 8 and 6 x 4.
36, 3 x 12 and 6 x 6.
48, 3 x 16 and 6 x 8.

So it's pretty much everything except for 32.
Have a great day!

6 0

3 years ago

Read 2 more answers

Can someone please help me with this ?

natulia [17]

13. 1,6

18. -15,12

19. -7, 1/2

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3 years ago

A diagram of Tracy’s deck is shown below, shaded blue. He wants to cover the

Lelechka [254]

Hey! We can’t see a picture of the problem.

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3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

To win a relay race, you must swim 200 yards before your opponent swims 190 yards. You swim at a pace of 50 yards every 40 secon

lora16 [44]

Answer:

You would win the race

Step-by-step explanation:

You would have to swim for 2 minutes and 40 seconds which is the same as 160 seconds.

The opponent would swim

$19 \times 8.5$

Which is161.5 seconds

This means you would win

6 0

3 years ago