Mattie uses the discriminant to determine the number of zeros the quadratic equation 0 = 3x2 – 7x + 4 has. Which best describes
2 answers:
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Answer:
6. Miles cientos decenas unidades
4 9 5 6
7. Catalina podrá hacer un cuadrado con longitud lateral de 4 cartones
8. 45000000 = 4.5 × 10⁶
0.000000000000056 = 5.6 × 10¹⁴
0.000000000034 = 3.4 × 10¹¹
Step-by-step explanation:
6. Los valores posicionales de dígitos son;
Miles cientos decenas unidades
4 9 5 6
7. El número de cuadrados que tiene Fernando = 12
El número de cuadrados que tiene Catalina = 16
El largo y el ancho de un cuadrado son iguales, por lo tanto tenemos;
largo × ancho = Área del cuadrado
largo = ancho = lado del cuadrado
Lado del cuadrado × Lado del cuadrado = Área del cuadrado
(Lado del cuadrado) ² = Área del cuadrado
Lado del cuadrado = √ (Área del cuadrado)
Para Fernando, Área del cuadrado = 12
Lado del cuadrado para Fernando = √12 = 2 · √3 cartones
Para Catalina, Área del cuadrado = 16
Lado del cuadrado para Catalina = √16 = 4 cartones
Por tanto, Catalina podrá realizar un cuadrado con longitud lateral de 4 cartones
8. 45000000 = 4.5 × 10⁶
0.000000000000056 = 5.6 × 10¹⁴
0.000000000034 = 3.4 × 10¹¹
Answer:
We want to find a solution of the system:
x^2 + y^2 > 49
y ≤ –x^2 – 4
Here we do not have any options, so let's try to find a general solution.
First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:
(x - a)^2 + (y - b)^2 = R^2
If we look at our first inequality, we can write it as:
x^2 + y^2 > 7^2
So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.
From the other equation, we would get:
y ≤ –x^2 – 4
This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.
Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.
You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:
by looking at the graph, we can see a lot of points that are solutions, like:
(0, -10)
(0, -15)
(2, -10)
etc.
