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Fiesta28 [93]
2 years ago
6

10 points

Mathematics
2 answers:
mixas84 [53]2 years ago
4 0

Answer:

y = -1/3 +3

Step-by-step explanation:

Tamiku [17]2 years ago
4 0

Answer:

y=-2x+3

Step-by-step explanation:

well you would use y=mx+b

1.  you need to find your slope by using y=mx+b which would be -2x

then your 3 will stay there

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Find the intercepts of the line.y=−5x−17
GaryK [48]

Answer:

Step-by-step explanation:

y = -5x - 17

in y = mx + b form, the y int is in the m position

y = mx + b

y = -5x - 17......so the y int (b) = -17 or (0,-17) <=== y intercept

u can also find the y intercept by subbing in 0 for x and solving for y

u can find the x intercept by subbing in 0 for y and solving for x

y = -5x - 17

0 = -5x - 17

5x = -17

x = -17/5......so the x intercept is -17/5 or (0,-17/5) <==== x intercept

5 0
3 years ago
Free
Leona [35]

Answer:

thanks appreciated it

3 0
2 years ago
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List at least four investment alternatives.
KatRina [158]
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8 0
3 years ago
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Audra was drawing a perpendicular bisector of segment ab with a compass . She started with a line segment AB . Then she placed h
aalyn [17]

Given that Audra was drawing a perpendicular bisector of segment AB with a compass. She started with line segment AB. Then, she placed her compass point on A and opened the compass more halfway to B.


Her next step will be "Using the width of the compass from the previous step, draw two arcs to the left and right of both A and B".



8 0
2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
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