Step-by-step explanation:
Volume of displaced water = (10cm)(10cm)(1.6cm)
= 160 cm^3
density = mass/vol of displaced water
= 3088 grams/160 cm^3
= 19.3 g/cm^3
P.S. This is most likely a pure gold medallion.
1.
a.) 2q + 5r
2(7) + 5(-2)
14 - 10 = 4
b.) 3(p + 6) + q + r Plug in the numbers
3(5 + 6) + 7 - 2 Solve inside the parentheses first
3(11) + 7 - 2
33 + 5 = 38
2.
a.) m(3m + 4n)
2(3(2) + 4(3))
2(6 + 12)
2(18) = 36
b.) n²(m + p²)
(3)²(2 + (-5)²)
9(2 + 25)
9(27) = 243
c.) 3m(8 + n) + n²
3(2) (8 + 3) + 3²
6(11) + 9
66 + 9 = 75
Y = kx
Plug in what we know:
5 = k(8)
5 = 8k
Divide 8 to both sides:
k = 0.625
Plug this back into the equation along with y = 15:
y = kx
15 = 0.625x
Divide 0.625 to both sides:
x = 24
Answer:
Step-by-step explanation:
Given
-- of the roadworks
Required
Determine the speed
In this case:
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