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Paha777 [63]
3 years ago
6

What is the sum of the coefficients in the expression of 4x^4 - x^3 - 2x^2 + 3 - 4

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

9514 1404 393

Answer:

  0

Step-by-step explanation:

The coefficients are the numerical values that are not exponents. Their sum is ...

  4 -1 -2 +3 -4 = 0

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We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
                                         0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
                                         t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
                                           = [- 12 ± √(144-64d) ] / (-32)
                                           = [- 12 ± √16(9-4d)] / (-32)
                                           = [- 12 ± 4√(9-4d)] / (-32)
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The answer to your question is t = 3/8 ±√(9-4d) / 8
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