Mechanical mouse has a ball that turns rollers inside. If friction is lost between the ball and the mousing surface, or between the ball and the rollers, the mouse fails to work. In order to assure good contact with the mousing surface, the ball must be fairly heavy. When you change directions with the mouse, you must make the ball change rolling directions--an action that inertia likes to prevent.
An optical mouse makes use of an LED and some optics to detect surface texture and the changes in it as the mouse is moved. There are no moving parts
Answer: C. Data type
Explanation:
data types are defined as the data storage format that a variable can store a data to perform a specific operation. Data types are used to define a variable before its use in a program. Size of variable, constant and array are determined by data types.
Answer:
The answer to this question can be defined as follows:
Explanation:
The term BPR stands for "business processes reengineering", It is the recreating of the core business process to improve product performance or reliability or lower costs.
- It generally includes analyzing business processes, which identifying sub-par or ineffective processes but identifying ways to dispose of or change it.
- IT important for improving changes, especially to shift in aspects of the work, its incorporation in business operations, or competitive strength change.
- It might contribute to making reconfiguration improvements, and is known as a BPR enabler.
In this way, writing the code in C++ we can say that it will be possible to make the coordinates on the planes.
<h3>Writing the code we have:</h3>
<em>#include <iostream></em>
<em>#include <cmath></em>
<em>#include <iomanip></em>
<em>using namespace std;</em>
<em>class Point{</em>
<em>private:</em>
<em>float x;</em>
<em>float y;</em>
<em>public:</em>
<em>Point(){ </em>
<em>x = y = 0;</em>
<em>}</em>
<em>Point(float x, float y){ </em>
<em>this->x = x;</em>
<em>this->y = y;</em>
<em>}</em>
<em>float getX(){ </em>
<em>return x;</em>
<em>}</em>
<em>float getY(){</em>
<em>return y;</em>
<em>}</em>
<em>float getDistance(){</em>
<em>return math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2));</em>
<em>}</em>
<em>string toString(){ </em>
<em>return "("(x1, y)","(x2, y2)")";</em>
<em>}</em>
<em>};</em>
See more about C code at brainly.com/question/17544466
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