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e-lub [12.9K]
3 years ago
15

Assuming that the user enters 45 and 62 as inputs for n1 and n2, respectively, what is the output of the following code snippet?

Computers and Technology
1 answer:
aev [14]3 years ago
8 0

Answer:

a) 4562

b) (a != b) || (a != c) || (b != c)

(a != b) && (a != c) && (b != c)

!((a == b) && (b == c) && (a == c))

Explanation:

a) The user input of 45 and 62 are received as a String (n1 and n2). Then result concatenate the value of 45 and 62 which is 4562. Result variable uses the concatenate operator '+'.

b)

(a != b) && (a != c) && (b != c) is correct as each of the individual condition must be true before it evaluate to true. Meaning a is not equals to b and a is not equals to c and b is not equals to c.

(a != b) || (a != c) || (b != c) is correct because it evaluate to true if at least one of the condition is satisfied.

!((a == b) && (b == c) && (a == c)) is correct because each individual condition is false and the logical combination of false and false and false equals false, then the negation of false is true

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Create a 4x5 matrix with ones everywhere and zeros on the last row.
Stells [14]

Answer:

#include <iostream>

using namespace std;

int main() {

   int a[4][5];//declaring a matrix of 4 rows and 5 columns.

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       {

           if(i==3)//initializing last row as 0.

           {

               a[i][j]=0;

           }

           else//initializing last row as 1.

           {

               a[i][j]=1;

           }

       }

   }

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       cout<<a[i][j]<<" ";//printing the matrix.

       cout<<endl;

   }

return 0;

}

Output:-

1 1 1 1 1  

1 1 1 1 1  

1 1 1 1 1  

0 0 0 0 0

Explanation:

I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.

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Answer:

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