To finish the demonstration that the quadrilateral JKLM is a rhombus we need to prove that side JK is congruent with side LM.
The length of a segment with endpoints (x1, y1) and (x2, y2) is calculated as follows:
![\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Substituting with points L(1,6) and M(4,2) we get:
![\begin{gathered} LM=\sqrt[]{(4-1)^2+(2-6)^2} \\ LM=\sqrt[]{3^2+(-4)^2} \\ LM=\sqrt[]{9+16^{}} \\ LM=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20LM%3D%5Csqrt%5B%5D%7B%284-1%29%5E2%2B%282-6%29%5E2%7D%20%5C%5C%20LM%3D%5Csqrt%5B%5D%7B3%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20LM%3D%5Csqrt%5B%5D%7B9%2B16%5E%7B%7D%7D%20%5C%5C%20LM%3D5%20%5Cend%7Bgathered%7D)
Given that opposite sides are parallel, all sides have the same length, and, from the diagram, the quadrilateral is not a square, we conclude that it is a rhombus.
Answer:
(-2.5,1)
Step-by-step explanation:
hope that helps
Step-by-step explanation:
If f(x)=3x+2and g(x)=x^2-9
find (f-g)(x)
f(x)- g(x) = [3x + 2] - [x^2 - 9]
= -x^2 + 3x + 11
1/2 hr* (5 miles/ 1 hr)= 2.5 miles.
2 1/2 hrs* (5 miles/ 1 hr)= 12.5 miles.
Malia runs 2.5 miles and 12.5 miles in 1/2 hr and 2 1/2 hrs respectively.
Hope this helps~
Answer:
$156 for 4 g
I did not rally understand how you worded your question so sorry if I got it wrong! <3
Step-by-step explanation:
$156 for 4 g =
$156 / 4 = $39 dollars for 1 g
$280 for 7 g =
$280/7 = $40 dollars for 1 g
