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dimulka [17.4K]
2 years ago
15

How many solutions does the following equation have? 7(y+3)=5y+8 A No solutions B Exactly one solution C Infinitely many solutio

ns
Mathematics
2 answers:
pickupchik [31]2 years ago
8 0

Answer:

Answer is B

Step-by-step explanation:

7y+21=5y+8

2y=-13

y= -6.5

iragen [17]2 years ago
3 0

Answer:

C

Step-by-step explanation:

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Last month Jim drove his car 2,718.3 miles. That brought the car’s total mileage to 87,416. What was the car’s mileage before la
stich3 [128]

To solve this problem you must apply the proccedure shown below:

1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.

2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:

87,416miles-2,718.3miles=84,697.7miles

Therefore, the answer is: 84,697.7 miles.

3 0
3 years ago
A woman saw oranges and mangos ad the market. She bought some oranges at 35 cents each and some mangoes at $1.00. if she bought
marysya [2.9K]

Answer: 20 oranges and 5 mangoes

Step-by-step explanation:

Define the following:

x = number of oranges

y = number of mangoes

Make the following system of equations:

x + y = 25

0.35x + 1.00y = 12.00

Solve for x:

y = 25 - x

⇒ 0.35x + 1.00(25 - x) = 12.00

⇒ 0.35x + 25 - x = 12.00

⇒ -0.65x = -13.00

⇒ x = 20

Solve for y:

20 + y = 25

y = 5

∴ 20 oranges and 5 mangoes were purchased.

8 0
1 year ago
The Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
kirza4 [7]

Answer:

Step-by-step explanation:

given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

Clerk          I           II           III    total

   

Pack      0.33          0.23    0.44 1

   

Defective 0.02 0.025    0.015  

   

Pack&def 0.0066 0.00575 0.0066 0.01895

a)  probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate

= P(II clerk) -P(II clerk and defective) = 0.23-0.00575=0.22425

b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)

=0.01895

c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3

=P(clerk 3 and def)/P(defective)

=\frac{0.0066}{0.01895} \\=0.348285

8 0
3 years ago
F of x equals 8 plus 2x eminus x squared ​
maria [59]

Answer:

Step-by-step explanation:

F

=

−

x

+

8

x

+

2

7 0
3 years ago
Read 2 more answers
I need this ASAP!!
Free_Kalibri [48]

Answer:

n = 4752 gallons

Step-by-step explanation:

Given

Dilivery: 396 dozen gallon in a day

RequirEd

determine the number of the gallon in a day

we understand that:

n= 396 dozen

unit conversion

1 dozen = 12

so

n = 396 dozen gallon

n = 396× 12

n = 4752 gallons

hence 4752 gallons milk is delivered daily

6 0
2 years ago
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