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Maru [420]
3 years ago
10

Suppose a runner completes one lap around a 400-m track in a time of 50 s. calculate the magnitude of the average velocity of th

e runner. express your answer in meters per second to the nearest integer.
Mathematics
2 answers:
maks197457 [2]3 years ago
6 0

Step-by-step explanation:

It is given that,

Distance covered by the runner, d = 400 m

Time taken to complete one lap, t = 50 s

We need to find the magnitude of the average velocity of the runner. Total displacement divided by total time taken is called the average velocity of the runner. Here, the total displacement is 0 as runner come back to same point.

It is given by :

v=\dfrac{displacement}{time}

v=\dfrac{0}{50}

v = 0

So, the average velocity of the runner is 0. Hence, this is the required solution.

marysya [2.9K]3 years ago
5 0
400:50=8(m/s)
........................
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The Kendal Company manufactures automobile engine parts. Running the manufacturing operations requires 12 watts (units of electr
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3 years ago
A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =
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6 0
4 years ago
2.the solution set of x +y =5 and x-y =3
Nataliya [291]

Answer:

Check the solution below

Step-by-step explanation:

2) Given the equation

x +y =5... 1 and

x-y =3 ... 2

Add both equations

x+x = 5+3

2x = 8

x = 8/2

x = 4

Substitute x = 4 into 1:

From 1: x+y = 5

4+y= 5

y = 5-4

y = 1

3) Given

x+3y =15 ... 1

2x+7y=19 .... 2

From 2: x = 15-3y

Substitute into 2

2(15-3y)+7y = 19

30-6y+7y = 19

30+y = 19

y = 19-30

y = -11

Substitute y=-11 into x = 15-3y

x =15-3(-11)

x = 15+33

x = 48

The solution set is (48, -11)

4) given

x/2 +y/3 =0 and x+2y=1

From 1

(3x+2y)/6 = 0

3x+2y = 0.. 3

x+2y= 1... 4

From 4: x = 1-2y

Substutute

3(1-2y) +2y = 0

3-6y+2y = 0

3 -4y = 0

4y = 3

y = 3/4

Since x = 1-2y

x = 1-2(3/4)

x = 1-3/2

x= -1/2

The solution set is (-1/2, 3/4)

5) Given

5.x=1/2 and y =x +1 then solution is

We already know the vkue of x

Get y

y= x+1

y = 1/2 + 1

y = 3/2

Hence the solution set is (1/2, 3/2)

6) Given

3x +y =5 and x -3y =5

From 3; x = 5+3y

Substitute into 1;

3(5+3y)+y = 5

15+9y+y = 5

10y = 5-15

10y =-10

y = -1

Get x;

x = 5+3y

x = 5+3(-1)

x = 5-3

x = 2

Hence two solution set is (2,-1)

6 0
3 years ago
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