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2 years ago

Determine whether the point (4,2) is in the solution set of the system of inequalities below. 4x + y < 2 y > –2

Mathematics

1 answer:

sladkih [1.3K]2 years ago

8 0

Answer:

False

Step-by-step explanation:

4x + y < 2

y > –2

Substitute the point into the inequalities and see if they are true

4(4) + 2 < 2

16+2 < 2

18 <2 False

2 > –2 True

Since one is false the point is not a solution

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Jack's family went out to dinner at a diner. The total bill was $78.99. The

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Answer:

The tax was 5.13

Step-by-step explanation:

Take the amount and multiply by the tax rate

78.99 * 6.5 %

Change to a decimal

78.99 * .065

Round to the nearest cent

5.13

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3 years ago

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A. 5<br> B. 8<br> C. 9<br> D. 12

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2 years ago

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5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago

Please help me with this problem and if you can show your work

ella [17]

Answer:

2.9

just answering wrong because i need points sorry

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3 years ago