40×+4y=-24 what is the equation for y

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

y=-6-10 x

Step-by-step explanation:

make y the subject

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⚡️⚡️Really need help, would appreciate it⚡️⚡️

pentagon [3]

Answer:

The answer to your question is letter A. Regular size is cheaper than Economy size by $0.0003 per gram

Step-by-step explanation:

Cost of 1 gr of economy size

5000 gr (5 kg) ------------------- $ 5.15

1 gr -------------------- X

x = 1 x 5.15 / 5000 = $0.0010

Cost of 1 gr of regular size

820 gr ------------------- $0.60

1 gr -------------------- x

x = 1 x 0.6 / 820 = $ 0.0007

Difference of cost = $0.0010 - $0.0007 = $0.0003

3 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$