Answer:
84
Step-by-step explanation:
A= 1/2• bh
A= 1/2•24(7)
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so
- The length of the fencing is 80 meters, so
Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:
Then substitute for y in the first:
b) To maximize A, find the zero of the first derivative:
So y = (80-40)/2 = 20 meters.
Answer:
Step-by-step explanation:
<u>We know that:</u>
- Area of shaded region = Area of square - Area of circles
- Radius of circle = 3 in
- Area of circle = πr²
- Area of square = s²
<u>Solution:</u>
- Area of shaded region = Area of square - Area of circles
- => Area of shaded region = (12²) - 4(22/7 x 3 x 3)
- => Area of shaded region = (144) - 4(22/7 x 9)
- => Area of shaded region = (144) - 4(198/7)
- => Area of shaded region = 144 - 792/7
- => Area of shaded region = 144 x 7/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 216/7 in²
Answer:
272.5 m²
Step-by-step explanation:
1/2x4x9=18
(9+18)/2=13.5. 13.5x11=148.5
(18+14)/2=16. 16x7=112
12+148.5+112= 272.5
Answer:
4
Step-by-step explanation:
