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2 years ago

7

Graph the line y=-3/4x+1

1 answer:

lesya [120]2 years ago

8 0

Step-by-step explanation:

That is what your line should look like :)

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Pls help help with this problem it's big hard thx

dimulka [17.4K]

It's asking for the coordinates of the treasure and I can't really see it right but it looks like the coordinate is about (-0.5, 1.5) it's not exact though cuz I can't really see it

8 0

2 years ago

Evaluate cos0 if sin0= sqrt(5)/3<br><br> a. 9/5<br> b. 2/3<br> c. 5/9<br> d. 3/2

Evgesh-ka [11]

Solution given:

$\sin( \alpha ) = \frac{\sqrt{5} }{3}$

so

P=√5

h=3

b= $\sqrt{3 {}^{2} - \sqrt{5} {}^{2} }$

b=2

so

$\cos( \alpha ) = \frac{b}{h} = \frac{2}{3}$

Note

$\alpha = 0$

<u>b</u><u>:</u><u>⅔</u>

8 0

2 years ago

Colin & Brian share a lottery win of £2100 in the ratio 4 : 1. Colin then shares his part between himself, his wife & th

Paraphin [41]

Answer:

His wife gets $336 more than his son.

Step-by-step explanation:

Colin and Brian:

Ratio of 4:1.

So Colin gets $\frac{4}{4+1} = \frac{4}{5}$ of the prize.

$\frac{4*2100}{5} = 1680$

Colin got $1680. Dividing between himself, his wife and their son:

Ratio of 2:5:3.

So Colin gets $\frac{2}{2+3+5} = \frac{2}{10}$ , his wife gets $\frac{5}{2+3+5} = \frac{5}{10}$ and his son gets $\frac{3}{2+3+5} = \frac{3}{10}$

Wife:

$\frac{5*1680}{10} = 840$

His wife got $840.

Son:

$\frac{3*1680}{10} = 504$

His son got $504.

How much more does his wife get over their son?

840 - 504 = 336

His wife gets $336 more than his son.

8 0

2 years ago

Help me what is this

AfilCa [17]

Answer:

Dog

Step-by-step explanation:

This seems to be a Chihuahua breed of a dog

7 0

2 years ago

Read 2 more answers

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

7 0

2 years ago