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3 years ago

Solve for the variables.

Mathematics

1 answer:

likoan [24]3 years ago

8 0

Answer:

blue

Step-by-step explanation:

70 = 2m so m=35

360 - 70 - 70 = 220

220/2 = 110 = n

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the third one. The company earned 74 billion dollars from 2008

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3 years ago

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Find the value of find the value of a -7 when a equals 19

Savatey [412]

Answer:

Step-by-step explanation:

You have to substitute a by 17 and then just subtract.

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3 years ago

What does the a equal in a/20=10

r-ruslan [8.4K]

Step-by-step explanation:

a/20=10

=a=10×20

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3 years ago

Use the quadratic formula to solve the equation. <br> x ^2 – 7 x –6 = 0<br> (Show work)

Vika [28.1K]

Given a quadratic equation

$ax^2+bx+c=0$

the quadratic formula states that the solutions are

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug your values to get

$x_{1,2}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1}$

Which evaluates to

$\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1} = \dfrac{7\pm\sqrt{73}}{2}$

So, the two solutions are

$x_1 = \dfrac{7+\sqrt{73}}{2},\quad x_2 = \dfrac{7-\sqrt{73}}{2}$

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3 years ago

Determine the projection of w onto u

natali 33 [55]

Answer:

c. 6.2i - 4.2j

Step-by-step explanation:

The vector projection when the angle θ not known can be calculated using the following property of the dot product:

$proj_uv=\frac{u\cdot v}{||u||^2} u$

Where the dot product of two vectors is given by:

$u\cdot v= $$\sum_{i=1}^{n} u_iv_i= u_1v_1+u_2v_2+...+u_nv_n$$$

And the magnitude of a vector is given by:

$||u||=\sqrt{u_1^2+u_2^2+...+u_n^2}$

Using the previous definition, let's calculate the projection of w onto u:

First let's calculate the dot product between w and u:

$u\cdot w =(9*19)+(-6*15)=171-90=81$

Now let's find the magnitude of u:

$||u||=\sqrt{9^2+(-6)^2} = 3 \sqrt{13}$

So:

$||u||^2=117$

Therefore:

$proj_uw=\frac{u\cdot w}{||u||^2} u=\frac{81}{117} \langle9,-6\rangle=\langle6.23,-4.14\rangle\approx6.2i-4.2j$

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3 years ago

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