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stepladder [879]

3 years ago

8

21. Find the perimeter of the triangle: 60 degrees, 60 degrees,

id="TexFormula1" title="4 \sqrt{15 } " alt="4 \sqrt{15 } " align="absmiddle" class="latex-formula">

1 answer:

barxatty [35]3 years ago

6 0

Answer:

120+ 4(square root)15

120+15.49=135.49

135.49 is the perimeter

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A craft stores sells ribbons in packages of different lengths the price of each package is shown which package offers the lowest

ankoles [38]

Answer:

Package 3 has the lowest unit price.

Step-by-step explanation:

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3 years ago

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A spool of ribbon is 85 inches long. riley needs to cut strips of ribbon that are 17 inches long. what are the possible numbers

Varvara68 [4.7K]

Answer:

80/14=5.7 OR 5 14 IN.

Step-by-step explanation:

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3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

HELP ME OUT HERE! PLS TELL ME HOW U GOT THE ANSWER TOO!

IgorC [24]

Answer: Choice C

$\begin{array}{|c|c|} \cline{1-2}x & y\\\cline{1-2}0 & 1\\\cline{1-2}2 & 2\\\cline{1-2}4 & 3\\\cline{1-2}6 & 4\\\cline{1-2}\end{array}$

=========================================================

Explanation:

There are four marked points on the line.

Each point is of the form (x,y)

The first or left most point is (0,1)
The second point is (2,2)
The third is (4,3)
The fourth is (6,4)

Each of these points is then listed in the table format as shown above.

There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).

Extra side notes:

The slope of this line is m = 1/2 = 0.5
The y intercept is 1 located at (0,1)
The equation of this line is y = 0.5x+1

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2 years ago

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How can you keep a math teacher-focused

jeka94

Answer:

how you would keep your math teacher focused

Step-by-step explanation:

try sending your teacher reminder emails, or put some sticky notes on their desk

5 0

2 years ago