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2 years ago

Please help im struggling

Mathematics

1 answer:

Gre4nikov [31]2 years ago

8 0

It might be c or d if not then sorry

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The Diaz family bought 7 bags of cookies. Each bag had 14 cookies. They have since eaten 29 of the cookies. How many cookies do

saveliy_v [14]

Answer:

They have 69 cookies left.

Step-by-step explanation:

7 x 14 = 98

98 - 29 = 69

6 0

3 years ago

Solve the equation. Then check your solution. 1.6a=-9.12

balu736 [363]

B.) a=-5.7
1.6(a)=-9.12
(a)=(-9.12)/(1.6)
a=-5.7

7 0

3 years ago

Read 2 more answers

If f(x)=ln(sin(2x)), f''(π/4) is equal to

Licemer1 [7]

Use the chain rule to compute the second derivative:

$f(x)=\ln(\sin(2x))$

The first derivative is

$f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}$

$f'(x)=2\cot(2x)$

Then the second derivative is

$f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'$

$f''(x)=-4\csc^2(2x)$

Then plug in π/4 for <em>x</em> :

$f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4$

4 0

3 years ago

Convert 5'5 into meters

sergey [27]

It will be around 1.6metres

hope it helps

4 0

2 years ago

Read 2 more answers

Frank weighs 160 pounds and is on a diet to gain two pounds a week so that he can make the football team. John weighs 208 pounds

gladu [14]

Answer: If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

Step-by-step explanation:

Let x = Number of weeks.

As per given question ,

Weight of Frank after x weeks = 160+2x (pounds)

Weight of John after x weeks = 208-3x (pounds)

When Weight of Frank= Weight of John

$\Rightarrow\ 160+2x= 208-3x$

$\Rightarrow\ 2x+3x= 208-160$

$\Rightarrow\ 5x= 48\Rightarrow\ x=\dfrac{48}{5}=9.6$

Weight of Frank after 9.6 weeks = 160+2(9.6) = 179.2 pounds

Weight of John after 9.6 weeks = 208-3(9.6)=179.2 pounds

Hence, If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

3 0

2 years ago

Please help im struggling​

Please help im struggling