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Grace [21]
2 years ago
11

Select the two pairs that are similar!

Mathematics
1 answer:
evablogger [386]2 years ago
6 0

It's the rectangle and squares(answer)

Step-by-step explanation:

Squares can be rectangles but rectangles cant be squares.

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What is the equation in point slope form for the line that is parallel to y=-8x-12 that contains the point (-3,3)
belka [17]

Answer:

The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)

Step-by-step explanation:

To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.

Given this information, we can use the point and slope and put them into the base form of point-slope form.

y - y1 = m(x - x1)

y - 3 = -8(x - -3)

y - 3 = -8(x + 3)

3 0
3 years ago
Solve the system of equations
Phoenix [80]
The correct answer is letter B, (6,-1).

When you substitute this ordered pair on the equations, you would found out is the correct one.
6 0
3 years ago
Read 2 more answers
The difference of 16 and a number, divided by 2
valentinak56 [21]

Answer:

8

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
2/3y = 4/5 solve the equation using inverse operations
Alisiya [41]

Answer:

y=6/5

Step-by-step explanation:

Hope this helps! Sorry if its wrong

6 0
2 years ago
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
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