Help me plz ASAP

In 2018, the number of students at The Villages High School was 975 and is increasing at a rate of 2.5% per year. Write and use

avanturin [10]

Answer:

$A(t)=975(1.025)^t$

In 2025,the number of students at the villages high school=1159

Step-by-step explanation:

We are given that in 2018

Number of students at the villages high school=975

Increasing rate,r=2.5%=0.025

We have to write and use of exponential growth function to project the populating in 2025.

$A_0=975,t=0$

According to question

Number of students at the villages high School is given by

$A(t)=A_0(1+r)^t$

Substitute the values

$A(t)=975(1+0.025)^t=975(1.025)^t$

t=7

Substitute the value

Then, the number of students at the villages high school in 2025

$A(7)=975(1.025)^7=1158.96\approx 1159$

8 0

3 years ago

Read 2 more answers

Wren is at the grocery store buying fruit. She buys x pounds of apples for $1.68 per pound. She buys 2 fewer pounds of grapes fo

Soloha48 [4]

Answer:

The number of pounds of apples is 4.5 and the number of pounds of grapes is 2.5

Step-by-step explanation:

Let

x ------> the number of pounds of apples

(x-2) -----> the number of pounds of grapes

we know that

Solve for x

so

therefore

The number of pounds of apples is 4.5 and the number of pounds of grapes is 2.5

4 0

3 years ago

Read 2 more answers

Can you please answer everything. What fraction every letter on their can run in a minute. Reward brainiest answer: 15 points

oksian1 [2.3K]

Student B:
1/2 / 4
= 1/2 x 1/4
= 1/8

student A:
2/3 / 6
= 2/3 x 1/6
= 1/9

student C:
4/5/ 8
= 4/5 x 1/8
= 1/10

answer
student B: 1/8 of a mile per minute
student A: 1/9 of a mile per minute
student C: 1/10 of a mile per minute

8 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$