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galben [10]
3 years ago
10

Squares of Binomials Please Help

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0
16x4=64; so we need two numbers that add up to 16 and their product should be 64. So x=8
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Justine paid 35.70 for a lego set that was on sale. The original price of the set was $42.00 what is the percentage discount for
Licemer1 [7]
15% because what you do is take $35.70 and subtract it from $42 then you get $6.3 and take that $6.3 and divide it from 42 and you get .15 but then just take the decimal away and it’s 15%.... don’t believe me just multiply 15% times 42
6 0
3 years ago
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Simplify to create an equivalent expression.<br> 10+4(-8 q-4)}10+4(−8 q−4)
ale4655 [162]

Answer:: -0.3125 + q + 0.5

If our equation is: 10 + 4(-8q - 4)  then we can simplify it in the next way:

first distribute the 4 with the content in the parentheses.

10 + 4(-8q - 4) = 10 -(8*4)q - 4*4 = 10 - 16 -32q = -6 -32q

now dependes on you, i like to put the negative sign outside  a parenthesis:

-(32q + 6)

and this is your simplified equation, just give solve it. <u>HOPES </u><u>THIS HELPS</u>

3 0
3 years ago
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The sum of 3 times m and 4 times m <br> M= 6
guapka [62]

Answer:42

Step-by-step explanation:

3 times 6 = 18

4 times 6 = 24

18 + 24 = 42

5 0
4 years ago
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A box witxh a height (x+5) cm has a square base with side x com. A second box with height (x+2) com has a square base with side
Eva8 [605]

Answer:

x=5.37 cm

Step-by-step explanation:

we know that

The volume of the box is

V=Bh

where

B is the area of the base of the box

h is the height of the box

<em>Box 1</em>

we have that

The area of the base is

B=x^2\ cm^2

h=(x+5)\ cm

The volume of the Box 1

is equal to

V_1=x^2(x+5)\ cm^3

V_1=(x^3+5x^2)\ cm^3

<em>Box 2</em>

we have that

The area of the base is

B=(x+1)^2\ cm^2

h=(x+2)\ cm

The volume of the Box 2

is equal to

V_2=[(x+1)^2(x+2)]\ cm^3

V_2=[(x^2+2x+1)(x+2)]\ cm^3

V_2=(x^3+2x^2+x+2x^2+4x+2)\ cm^3

V_2=(x^3+4x^2+5x+2)\ cm^3

Equate the equation of Volume 1 to the equation of Volume 2

(x^3+5x^2)=(x^3+4x^2+5x+2)

(5x^2)=(4x^2+5x+2)

5x^2-4x^2-5x-2=0

x^2-5x-2=0

Solve the quadratic equation by graphing

using a graphing tool

The solution is x=5.37 cm

see the attached figure

8 0
4 years ago
PLEASE HELP! 
NNADVOKAT [17]

D is ur answer bro good luck


8 0
3 years ago
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