Determine whether the given number is an irrational number or a rational number and place it in its representing

Which of the following are exterior angles?

Bezzdna [24]

Answer:

B. ∠6, D. ∠2, E. ∠3, F. ∠4

Step-by-step explanation:

∠2, ∠3, ∠4 & ∠6 are exterior angles as they present outside the triangle. Here, only ∠1 & ∠5 are present in the interior of the triangle.

Hope it helps ⚜

4 0

2 years ago

Read 2 more answers

Sam is collecting pennies. On the first day of the month, Samnis given 16 pennies. Each day after that he gets 4 more pennies. W

gtnhenbr [62]

Answer:

The answer is 4n + 16

Step-by-step explanation:

N is the number of days that pass by. Each day Sam gets 4 more, meaning you would multiply the number of days by 4, before adding that number to the original number of pennies, which was 16.

3 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ (Approximated)

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ (Approximated)

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ (Approximated)

4 0

4 years ago

what is the example of a product that will have the same number of zeros in the factors and the products? what is one example of

Natalka [10]

Answer:

same: 30×40 = 1200
different: 20×50 = 1000

Step-by-step explanation:

Same: 30×40 = 1200 . . . . . 2 zeros in the factors; 2 in the product

Different: 20×50 = 1000 . . . 2 zeros in the factors; 3 in the product

__

Same: 0.3×0.4 = 0.12 . . . . no zeros in the factors; no zeros in the product

Different: 0.2×0.4 = 0.08 . . . no zeros in the factors; 1 zero in the product after the decimal point

_____

For a product, the number of zeros will be different if the combined factors of the numbers increase the number of factors of 10 beyond the sum of the factors of 10 of the numbers being multiplied.

Example: neither 2 nor 5 has a factor of 10, but their product does.

__

For a product that is a decimal fraction, the number of leading zeros will increase if the product of the mantissas of the numbers is less than 10. The number of trailing zeros will increase under the conditions discussed above. (0.25×0.4 = 0.100)

_____

Additional comment

Here, the term "mantissa" is used to refer to the portion of the number written in scientific notation that multiplies the power of 10.

3 0

3 years ago

Y = -5x y = x-6 What is the answer

deff fn [24]

Answer:

(1,-5)

Step-by-step explanation:

8 0

3 years ago