V = s²h
<span>150 = s²h </span>
<span>150 = s²(3/2)s </span>
<span>(2/3)150 = s³ </span>
<span>100 = s³ </span>
<span>s = ∛100 (approx 4.642 in) </span>
We are required to compare the magnitude for two earthquake intensity:
the larger intensity is 7.9
the smaller intensity is 3.7
thus the ratio of the intensity will be:
(larger intensity)/(smaller intensity)
=7.9/3.7
=2.135
~2
Thus we conclude that:
The larger earthquake's intensity was 2 times as great as the smaller earthquake's intensity.
I think Its 6.............
Solve for f:(i - 47/12) + f = 18
(i - 47/12) + f = f + (-47/12 + i):
f + (-47/12 + i) = 18
Subtract -47/12 + i from both sides:
Answer: f = 263/12 - i
Answer:
290
Step-by-step explanation:
