In a Euclidean<span> space, the </span>sum<span> of measures of these three </span>angles of<span> any </span>triangle<span> is invariably equal to the straight </span>angle
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To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.
The two numbers are both 9, so its safe to say that the median is 9.
to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).
Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3
The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.
Answer:
x ≈ 26.4
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos47° = 
= 
= 
( multiply both sides by x )
x × cos47° = 18 ( divide both sides by cos47° )
x = 
≈ 26.4 ( to the nearest tenth )
Answer:
7.
I) must be true
II) 1 - 1 < 2 - 4 --> false
III) (-10)*(-10) < 1*1 --> false
IV) 1/2 < 2/10 --> false
So (B) 1 must be true
8.
x!·(x + 1)!/2 = (x + 1)!^2 / (2·(x + 1)) = (17 + 1)!^2 / (2·(17 + 1)) = 18!^2 / 6^2
(D)
9.
2·√3·6 = √((2·√3)^2 + 6^2)·h --> h = 3 --> (C)
Answer:
x³ = 343, if x = 7
Step-by-step explanation:
If x = 7, then:
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