What is the ordered pair rule for a 270 degree counterclockwise rotation?

10 people who build at the same rate can frame a house in 6 days. What fractional part of a house can 4 people frame a house in

Alina [70]

10 people who build at the same rate can frame a house in 6 days. That means it will take one person $10\times6=60$ days to finish the house.

Which means that it will take 4 people $\frac{60}{4}=15$ days to finish the house.

So, the fractional part of the house 4 people can frame in 3 days will be $\frac{3}{15}=\frac{1}{5}$

Thus, Option D is the correct answer.

8 0

3 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

3 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0

3 years ago

You and a friend or 2 pizzas from pizza hut. you ate 7/8 of one pizza and 3/4 of the other pizza. find the product of the amount

kotegsom [21]

13/8 or 1 5/8
3/4 becomes 7/8 when add it is 13/8

6 0

3 years ago

Determine the probability of a negative result for a batch of size 10 if the positivity rate

Vlad1618 [11]

The probability of a negative result for a batch will be "0.3487".

Given values are:

Positivity rate,

p = 10% or, 0.1

Batch size,

n = 10

Now,

The probability of negative result will be:

→ $P (batch \ negative) = (1-p)^n$

By substituting the values, we get

→ $=(1-0.1)^{10}$

→ $= (0.9)^{10}$

→ $= 0.3487$

Thus the answer above is right.

Learn more about the probability here:

brainly.com/question/17927863

8 0

2 years ago