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leonid [27]
3 years ago
13

Help me please!!!!!!

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.

The two numbers are both 9, so its safe to say that the median is 9.

to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).

Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3

The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.

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The circumscribing circle O and the inscribed circle of triangle ABC have the same center. Which of the following constructions
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Answer:

Construct perpendicular lines & construct angle bisectors

Step-by-step explanation:

I saw someone ask the same question and they had that anwser^

4 0
3 years ago
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Let 40 x 55 = n. Which of the choices shown is also equal to n?
labwork [276]
D) (10 x 55) + (10 x 55) + (10 x 55) + (10 x 55)

use distributive rule to factor out 55:
55 (10+10+10+10) = 55×40
5 0
3 years ago
I need help i don’t understand
ch4aika [34]

9514 1404 393

Answer:

  A) J(-3, 1), ...

Step-by-step explanation:

All of the answer choices list point J' first, so it is convenient to use that as an example.

Point J on the given graph has coordinates (x, y) = (3, 2). The x-coordinate is 3 because the point is 3 units to the right of the y-axis.

The problem statement tells you to translate this point 6 units to the left. When you move it 6 units left, it will move left 3 units to the y-axis, then left 3 more units to have an x-coordinate of 3 -6 = -3. That is, each unit of movement to the left subtracts 1 from the x-coordinate. The x-coordinate of J is 3, so the final point J' will have an x-coordinate of 3 - 6 = -3.

At this point, you have enough information to make the correct answer selection. Only one answer choice has the x-coordinate of J' as -3.

__

The other coordinates are translated using similar logic. The y-coordinate of J is 2. Translating it down 1 unit subtracts 1 from the y-coordinate to make it be 2 -1 = 1. Then the coordinates of J' are (-3, 1).

We write the translation rule as ...

  (x, y) ⇒ (x -6, y -1)

This means the coordinates of each translated point have 6 subtracted from the original x-coordinate, and 1 subtracted from the original y-coordinate. The other coordinates of the figure are ...

  I(2, 4) ⇒ I'(2 -6, 4 -1) = I'(-4, 3)

  H(5, 5) ⇒ H'(5 -6, 5 -1) = H'(-1, 4)

  G(4, 1) ⇒ G'(4 -6, 1 -1) = G'(-2, 0)

3 0
3 years ago
For f(x) = 4x+ 1 and g(x) = x2 - 5, find (f+ g)(x).
horrorfan [7]

Answer:

x^2+4x-4

Step-by-step explanation:

4x+1+x^2-5

x^2+4x-4

6 0
3 years ago
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6.
Snowcat [4.5K]
The vertex of the graph is (2,-4). It is a minimum as it is the lowest point on the parabola facing upwards. This would be option C.
6 0
3 years ago
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