Answer: (100th answer)
perimeter of field b = 260 m
Step-by-step explanation:
First we have to find what is 7/12 of 108?
Well first we need to know what 1/12 of 108 is. Which means we do 108/12. That equals 9. so if 1/12 of 108 = 9
then 7/12 of 108 is 9*7 which is 63.
The width of field A is 63 plus its length, width again and its length again would be its perimeter or
2l + 2w is its perimeter, where l is length and w is width
108*2+63*2= perimeter
216+126 = ?
342 is the perimeter of field A.
We aren't done though.
We have to find 5/6 of 342.
1/6 of 342 is 342/6
342/6 = 52
1/6 of 342 = 52 meaning 5/6 of 342 is equal to 5*52.
5*52 = 260
the perimeter of field b is 260
