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Bas_tet [7]
3 years ago
10

Find f(-x) of the function 4x^2+2x-4 SOMEONE PLEASE HELP ASAP WORTH 50 POINTS

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

Given:

The function is:

f(x)=4x^2+2x-4

To find:

The value of f(-x).

Solution:

We have,

f(x)=4x^2+2x-4

Substituting x=-x in the given function, we get

f(-x)=4x^2-2x-4

Therefore, the required function is f(-x)=4x^2-2x-4.

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SinA=√1-x÷√1+X<br> Find the value of cosA
Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = \sqrt{1} - x

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6 0
2 years ago
**Solve by Elimination<br> 3 + 2x - y = 0<br> -3-7y = 10x<br> 7) x =<br> 8) y =
timofeeve [1]
Answer:

Explanation:

3 + 2x - y = 0
Or 2x - y = -3 (1)

-3-7y = 10x
Or -10x - 7y = 3 (2)

2x - y = -3 (1)
-10x - 7y = 3 (2)
———————

Multiply 5 to (1)

5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1

Plug y value in (1)

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Therefore, x = -1 and y = 1
7 0
3 years ago
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