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inna [77]
3 years ago
12

Some steps to construct angle MNT congruent to angle PQR are listed below.

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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An angle bisector of a triangle divides the opposite side of the triangle into segments 8 cm and 2 cm long. A second side of the
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Bisector angle

Then apply relation

8/2 = L3 / L2

L2 = 4.9

then

8/2= 4 = L3/ 4.9

So, L3 = 4•4.9 = 19.6 cm

Also

8/2= 4= 4.9/L2

So ,L2= 4.9/4 = 1.2 cm

Then, answer is OPTION D) 19.6 cm, 1.2 cm

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It takes a boat going upstream 3 hours to cover the same distance, as it would cover in 2
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15km

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What is 10.903 estimate to
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Answer:Its A or C

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2 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
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