Answer:
This statement is true for any N vectorial space.
By definition u·v=|u|·|v|·cos(α), where α is the angle between u and v.
If -1≤cos(α)≤1, we can assume:
|u·v|=||u|·|v|·cos(α)|=|u|·|v|·|cos(α)|≤|u|·|v|
Answer: Divide using synthetic division. If the remainder is 0, then x+2 is a factor.
x+2 is not a factor.
I put your question into a website, I don't know if that will help you but that's the best I can do, I don't even know the answer
Answer:
a
Step-by-step explanation:
if im correct its a could be wrong
Answer:
The correct equation is D.) 6x - 7y = -11
Step-by-step explanation:
