Ask question

Ask question

All categories

4 years ago

12

GIVING 50 POINTS AND BRAINALIST FOR DA RIGHT ANSWER >:>Jordan has 300 pieces of candy. He gives Adrian ¼ pieces, 10% was g

iven to Darien and he gave his little brother 25 pieces. Explain in writing (typing) how to find the number of pieces each person received then explain in writing (typing) how to find the number of pieces Jordan has left. (Remember to write 5 or more complete sentences)

1 answer:

wel4 years ago

3 0

Answer:

170 pieces left

Step-by-step explanation:

There are total 300 pieces of candy.

Adrian gets 1/4 of total

<u>Multiply the total number by 1/4, to find the number Adrian gets:</u>

300*1/4 = 75

Darien gets 10% of total.

<u>10% is equal to 10/100 = 1/10. Multiply 300 by 1/10 to get the number Darien gets:</u>

300*1/10 = 30

The little brother gets 25 pieces.

<u>Number of pieces Jordan has given:</u>

75 + 30 + 25 = 130

<u>Number of pieces left:</u>

300 - 130 = 170 pieces

You might be interested in

1+4=5<br> 2=5=12<br> 3=6=21<br> 8+11=?

Irina18 [472]

The answer for the last on is 19

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!!!! WILL MARK BRAINLIEST FOR FIRST CORRECT ANSWER!!!!

Alona [7]

4/5 is the answer.
The formula is y=mx+b, where m is the slope

4 0

3 years ago

Read 2 more answers

Rays dad bought a vintage car for $23000. If it increases in value 3% a year, how much will it be worth in 7 years?

kirill115 [55]

Answer:

It should be $27830 if I'm reading this right.

Step-by-step explanation:

3% of $23000 is $690

$690 * 7 = $4830

$23000 + $4830 = $27830

6 0

3 years ago

Read 2 more answers

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

HELP ON QUESTION FOR TEST PLEASE!!!

Lyrx [107]

Answer:

C it is porportinal Brainleist pls

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers