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trasher [3.6K]
2 years ago
11

It was John's birthday, 1/2 of his cupcakes were choco lava, the other half was strawberry. There were 10 strawberry cupcakes. R

ick ate 2/4 of choco lava cupcakes. Steward ate 1/10 of the strawberry How much did Rick and Steward eat?
Mathematics
2 answers:
julsineya [31]2 years ago
7 0

Answer:

6 cupcakes or 6/10 or 3/5

Step-by-step explanation:

igomit [66]2 years ago
4 0
If there were 10 strawberry cupcakes then chocolate would have the same number as 10= 1/2. Then 2/4 can be simplified to 1/2 meaning that Rick are 1/2 of 10 and 1/10 is just one out of the 10 strawberry cupcakes.

Rick ate 5 Chocolate Cupcakes

Steward are 1 Strawberry Cupcake
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Help me jim! geometry homework
Maksim231197 [3]

Question 1

The angles 52 degrees match up. So if the sides are in proportion, then the triangles are similar.

Notice how 8/12 = 18/27 is a true equation. So the sides are in proportion to one another.

Therefore, the triangles <u>are similar</u>. I used the <u>SAS similarity theorem</u>.

================================================================

Question 2

Let's find the missing angle of the triangle on the right. For now, make that missing angle to be x.

Rule: For any triangle, the three angles always add up to 180

x+70+32 = 180

x+102 = 180

x = 180-102

x = 78

The missing angle of the triangle on the left is 78 degrees

Repeat for the other triangle as well

y+78+32 = 180

y+110 = 180

y = 180-110

y = 70

Both triangles have the angles 32, 70, 78 in whatever order you wish.

Since the angles match up like this, <u>the triangles are similar</u> because of the <u>AA Similarity theorem</u>

Technically, we only need 2 pairs of congruent angles at minimum. But having 3 congruent pairs doesn't hurt either.

================================================================

Question 3

We have a pair of congruent 54 degree angles shown. There's another pair of angles at the very top that overlap (aka shared angles).

Since we have two pairs of congruent angles, <u>the two triangles are similar</u>.

This time we use the <u>AA Similarity theorem</u>

================================================================

Question 4

Let's divide the longest side of the bottom triangle by the longest side of the triangle on top

48/32 = 1.5

Now let's divide the shortest sides of each triangle in the same order

36/24 = 1.5

Repeat for the middle-most sides

45/30 = 1.5

We get the same linear scale factor 1.5 each time. Therefore, <u>the triangles are similar</u> due to the <u>SSS Similarity theorem</u>

================================================================

Question 5

Any angle is equal to itself due to the <u>reflexive property</u>. So that will go for reason number 2.

Reason 3 is <u>SAS similarity</u> because we have the sides in proportion (statement 1) and the angles are congruent (statement 2).

3 0
2 years ago
Solve 2,401 = 76 – 2x.
statuscvo [17]
X = -1162.5



Subtract 2,401 from both sides.

0 = 76 - 2401 - 2x

0 = -2325 - 2x

Add 2x on both sides.

2x = -2325

Divide both sides by 2.

x = -2325 / 2

x = -1162.5

There is the answer.



Please consider marking this answer as Brainliest to help me advance.
3 0
3 years ago
Read 2 more answers
Which one is not true?
Charra [1.4K]

Answer:

D

Step-by-step explanation:

-61>-10>0 is not true

The greater the negative number is the smaller it becomes.

8 0
3 years ago
10 POINTS! PLEASE HELP!! The illustration shows a compact disc tray that holds five CDs. The radius of each compact disc is 9 cm
MariettaO [177]

We can see that there are 5 CDs, each of radius 9 cm

<u>Area occupied by 1 disc:</u>

Area of a circle = πr²

Area of disc = π(9)²

Area of disc = 3.14 * 81 = 254 cm²

<u>Area occupied by 5 discs:</u>

Area occupied by 5 discs = Area occupied by 1 disc * 5

Area occupied by 5 discs = 254 * 5

Area occupied by 5 discs = 1270 cm²

3 0
2 years ago
Three people build a rectangular shed 8 ft wide, 6 ft long, and 7 ft high. How many cubic feet does the shed contain?
dusya [7]
8x6x7= 336
Your answer is 336 ft^3
7 0
3 years ago
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